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10y^2+37y+7=0
a = 10; b = 37; c = +7;
Δ = b2-4ac
Δ = 372-4·10·7
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-33}{2*10}=\frac{-70}{20} =-3+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+33}{2*10}=\frac{-4}{20} =-1/5 $
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